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Let me make sure I understand. Arrays are getting passed into the function. Array have member functions above and beyond the ones that Adobe lists. Are there other Java member functions that may be useful? How would I find them?

Comment by James Mohler

Regarding finding available Java methods: In order to find this, we need to get the Java class that is being used with the given data type/object we're working with. From there it's just a matter of calling that class' getMethods() function and iterating over the results; which is an array of Java Method classes. Here's an example: <code></code> exampleArray = []; methods = exampleArray.getClass().getMethods(); // If you want to see the raw result // writeDump(methods); arrayEach(methods, function(method) { writeOutput("#method.getName()#"); });  

Comment by Tony Junkes

How does the Java clone() function compare to ColdFusion's duplicate() function?

Comment by Carl Von Stetten

Sorry about the formatting - I don't seem to be able to fix it!Arrays are based on java.util.AbstractList. You can find the super class by doing:---exampleArray = [];writeDump(exampleArray.getClass().getSuperClass().getSuperClass().getName());writeDump(exampleArray.getClass().getSuperClass().getSuperClass().getSuperClass().getName());---In ACF (2018) that’ll give you:---java.util.ArrayListjava.util.AbstractList---In Lucee (5) that’ll give you:---lucee.runtime.type.util.ArraySupportjava.util.AbstractList---You can then look up the methods of java.util.AbstractList

Comment by aliaspooryorik

To be honest - I don't know. I'd imagine that <code>duplicate</code> is using <code>clone</code> under the hood. If you use either you get back the same java datatype.

Comment by aliaspooryorik

Here is a link to the JavaDocs for AbstractList: <a href="https://docs.oracle.com/javase/8/docs/api/java/util/AbstractList.html" rel="nofollow">https://docs.oracle.com/javase/8/docs/api/java/util/AbstractList.html</a>  

Comment by Peter Freitag

Whatever you do, put these calls to the underlying java methods in wrapper so that you never call it but one spot in your code base so that whenever Adobe breaks it in a future version cause it's "undocumented" you won't have to fight with your codebase for 6 months.

Comment by Justin Treher

@Justin Thanks for the comment. In the past I would have agreed with you, these days I think taking advantage of the Java methods is a reasonable thing. These methods are undocumented in CFML land, but they are documented in Java land. So I take your point that Adobe may change the Java datatype they use for say a ColdFusion array but it is highly unlikely. Lucee and ColdFusion use a slightly different inheritance tree, but these methods still work on both engines. It is of course possible (although unlikely) that Adobe changes the underlying datatype.  However you should have unit tests, so you will know as soon as you update ColdFusion that there is an issue and the change will be the same throughout your code base. If you don't have code coverage then any change to ColdFusion or the JVM version is a bit of a risk.

Comment by aliaspooryorik

In addition to the above function, there is a chance that you want to retain common elements from both sets. function retainCommonElements(a, b) { var result = a.clone(); result.retainAll(b); return result; } set1 = [0,2,4,6]; set2 = [0,3,6]; result = retainCommonElements(set1, set2); writeDump(result); // 0, 6 writeDump(set1); // 0, 2, 4, 6

Comment by Tushar Bhaware

Thanks Tushar. I did do a couple of related posts which people may be interested to read and it's quite hard to find related posts on this community portal so here they are: <a href="https://coldfusion.adobe.com/2019/01/intersection-of-arrays/">Intersection of Arrays [https://coldfusion.adobe.com/2019/01/intersection-of-arrays/]</a> <a href="https://coldfusion.adobe.com/2019/01/finding-symmetric-difference-two-arrays/">Finding The Symmetric Difference Between Two Arrays [https://coldfusion.adobe.com/2019/01/finding-symmetric-difference-two-arrays/]</a>  

Comment by aliaspooryorik